You can attack this is two ways (I think!):

1) Set the “relevant” property on the border to “-print” (this will keep it visible on the screen but won’t print it….essentially like the “Visible (Screen Only)” option on the object itself). Please see Stefan’s article on version specific implementations first though (http://forms.stefcameron.com/2007/09/27/presence-vs-relevance/. However, I think this will actually remove the whole border so it might look a little odd when printing.

2) You could try to reverse the script in the “prePrint” event, then execute it again in the “postPrint” event.

John.

No worries Mark, try this:

yourFieldName.ui.oneOfChild.border.relevant = “-print”;

Let me know if that doesn’t work.

Thanks John,

I appreciate your efforts and time with trying to help me solve this. We will have to just live with the colors being printed until i can come up with something else but if you think of anything else i would appreciate more input. thanks again.

MJ

Hi Stefan,

Is it possible to change object type for instance textfield to drop-down list at runtime?

Thank you for your help.

Thank you Stefan.

Actually, I had the show/hide solution working and thought there might be a more elegant solution to accomplish the same thing.

Abu Saleh,

Setting a fill on a circle or rectangle is a little tricky. In this case, the XFA object will look like this (for a circle or rectangle):

<draw>
    ...
    <value>
        <arc|rectangle>
            ...
        </arc|rectangle>
    </value>
</draw>

When setting a solid fill, you need to set the following XFA structure inside the <arc> or <rectangle> value type node:

<fill presence="visible*">
    <color>R,G,B</color><-- start -->
    <linear type="toRight*|toLeft|toTop|toBottom">
        <color>R,G,B</color><-- end -->
    </linear>
</fill>

(* = default)

The problem is that, initially, none of those nodes exist so you need to create them.

Here’s a sample script that sets a linear to-right fill on a circle object:

// JavaScript:

// create start color
var startColorNode = xfa.form.model.createNode("color");
startColorNode.value = "255,0,0"; // red

// create end color
var endColorNode = xfa.form.model.createNode("color");
endColorNode.value = "255,255,0"; // yellow

// create linear node for fill type
var linearNode = xfa.form.model.createNode("linear");
linearNode.type = "toRight"; // start on left, end on right
linearNode.nodes.append(endColorNode); // add end color

// create fill node for arc (circle)
var fillNode = xfa.form.model.createNode("fill");
fillNode.nodes.append(startColorNode); // add start color
fillNode.oneOfChild = linearNode; // add fill type

// remove old arc fill (if any) and set new one
if (Circle1.value.arc.resolveNode("#fill"))
{
    Circle1.value.arc.nodes.remove
    (
        Circle1.value.arc.resolveNode("#fill")
    );
}
Circle1.value.arc.nodes.append(fillNode);

For a radial fill, you need to set the following XFA structure inside the <arc> or <rectangle> value type node:

<fill presence="visible*">
    <color>R,G,B</color><-- start -->
    <radial type="toEdge*|toCenter">
        <color>R,G,B</color><-- end -->
    </linear>
</fill>

(* = default)

The code would therefore be very similar to the example above, creating a new radial node rather than a linear node.

For the solid fill case, the XFA structure is much simpler:

<fill presence="visible*">
    <color>R,G,B</color><-- start -->
</fill>

@Neha,

Yes, you have to do it field-by-field, recursively into all containers. My Process All Fields script can help you with that.